PART E.)In terms of the trigonometry ratios for triangle BCD, what is the length of line BD. Insert text on the triangle to show the length of line BD. When you’re done use the formula for the area of a triangle area equals 1/2 times base times height write an expression for the area of triangle ABC this when you do this base your answer on what u did in part E

Question

RaiyneF227136 RaiyneF227136

03-11-2022
Mathematics

contestada

PART E.)In terms of the trigonometry ratios for triangle BCD, what is the length of line BD. Insert text on the triangle to show the length of line BD. When you’re done use the formula for the area of a triangle area equals 1/2 times base times height write an expression for the area of triangle ABC this when you do this base your answer on what u did in part E

Respuesta :

Otras preguntas

what is the cell cycle??

what It Trigonometry ?

Over what period of time would you expect to see large changes in mountains,canyons,and similar features of the earth?

The following statements about carbon dioxide are true EXCEPT a. It can be prepared by the action of acid on CaCO₃ b. It is used in fire extinguishers c. It d

How many midgets can sit in a clown car if the car can hold 4 clowns from door to door and 3 people from front seat to back seat. Two midgets fit across 1 clow

What is the purpose of sensory adaptation

solve for x: 2x^2+4x-16+=0

Using the equation y=ax^2+bx+c to represent a parabola on a graph, which statement is true?1) If b is negative, the parabola opens downward2) If a is negative,

A mouse population starts with 2,000 mice and grows at a rate of 5% per year. The number of mice after t years can be modeled by the equation, P(t)=2000(1.05)^t

what colors are birds are attracted 2

AriadnneG480346 AriadnneG480346 · Answer 1 · 2022-11-03T13:24:55+01:00

Sine formula

[tex]\sin (angle)=\frac{\text{opposite side}}{hypotenuse}[/tex]

Considering angle C from triangle BCD, the opposite side is side BD and the hypotenuse is side BC which length is a units. Then:

[tex]\begin{gathered} \sin (\angle C)=\frac{BD}{a} \\ \text{ Isolating BD} \\ \sin (\angle C)\cdot a=BD \end{gathered}[/tex]

The area of a triangle is calculated as follows:

[tex]A=\frac{1}{2}\cdot\text{base}\cdot\text{height}[/tex]

In triangle ABC the base is b units long and its height is segment BD, then the area of triangle ABC is:

[tex]\begin{gathered} A=\frac{1}{2}\cdot b\cdot BD \\ \text{ Substituting with the previous result:} \\ A=\frac{1}{2}\cdot b\cdot a\cdot\sin (\angle C) \end{gathered}[/tex]