aAs given by the question
There are given that the equation
[tex]x^2-6x+10=0[/tex]
Now,
The solution of the Aaliyah is:
[tex](x-3)^2=-1[/tex]
Then,
The next step of the given solution is:
[tex]\begin{gathered} (x-3)^2=-1 \\ x-3=\sqrt[]{-1} \end{gathered}[/tex]
According to the concept of complex number
[tex]i=\sqrt[]{-1}[/tex]
So,
[tex]\begin{gathered} x-3=\sqrt[]{-1} \\ x-3=i \\ x=i+3 \end{gathered}[/tex]
