The acceleration of the block = 6.83 m/s²
Explanation:The free body diagram representing the given description is:
The mass of the block, m = 45.8 kg
The angle of inclination, θ = 44.2°
Acceleration due to gravity, g = 9.8 m/s²
Applying Newton's second law of motion
∑F = ma
mgsinθ = ma
Divide both sides by m
[tex]\begin{gathered} \frac{mg\sin \theta}{m}=\text{ }\frac{ma}{m} \\ a\text{ = gsin}\theta \end{gathered}[/tex]a = 9.8 sin (44.2)
a = 9.8(0.697)
a = 6.83 m/s²
