Recall that the quadratic formula states that, the solutions to the quadratic equation
[tex]ax^2+bx+c=0[/tex]
are
[tex]\frac{-b\pm\sqrt{(-b)^2-4ac}}{2a}.[/tex]
Now, in the given equation, a=-1 ,b=-6, and c= 8. Therefore, the solutions to the equation are:
[tex]x=\frac{6\pm\sqrt{36+32}}{-2}.[/tex]
Simplifying the above result, we get:
[tex]x=-3\pm(-1)\sqrt{17}.[/tex]
Answer:
[tex]\begin{gathered} x_1=-3+\sqrt{17,} \\ x_2=-3-\sqrt{17}. \end{gathered}[/tex]
