Given:
There are given the equation:
[tex]-x^3+22x^2-121x=0[/tex]
Explanation:
According to the question:
We need to find the value of x by using the factoring:
S0,
From the equation:
[tex]-x^{3}+22x^{2}-121x=0[/tex]
Tthen,
[tex]\begin{gathered} -x^{3}+22x^{2}-121x=0 \\ -x(x^2-22x+121)=0 \end{gathered}[/tex]
Then,
[tex]\begin{gathered} -x(x^2-22x+121)=0 \\ x(x-11)^2=0 \\ x=0; \\ x-11=0 \\ x=11 \end{gathered}[/tex]
Final answer:
Hence, the value of x by using factor method is shown below:
[tex]x=0,11[/tex]
