ANSWER:
(a) 108 J
(b) 0 J
(c) 108 J
STEP-BY-STEP EXPLANATION:
(a)
Express the relation between horizontal component of work done and force on the crate:
[tex]W_h=F_h\cdot d[/tex]
Here Wh is the horizontal component of the work done on the crate and Fh is the horizontal component of force and d is the distance of the crate across the floor.
Replacing:
[tex]\begin{gathered} W_h=36\cdot3 \\ W_h=108\text{ J} \end{gathered}[/tex]
(b)
Express the relation between vertical component of work done and force on the crate:
[tex]W_v=F_v\cdot d[/tex]
Here Wv is the vertical component of the work done on the crate and Fv is the vertical component of force and d is the distance of the crate across the floor.
Replacing:
[tex]\begin{gathered} W_h=27\cdot0 \\ W_h=0\text{ J} \end{gathered}[/tex]
(c)
Express the relation for total work done by the 45 N force:
[tex]\begin{gathered} W_{\text{total}}=W_h+W_v \\ \text{ replacing} \\ W_{\text{total}}=108+0 \\ W_{\text{total}}=108\text{ J} \end{gathered}[/tex]
