Answer:
[tex]524\text{ J}[/tex]Explanation:
Here, we want to get the amount of heat energy needed
Mathematically:
[tex]Q\text{ = mc}\Delta T[/tex]where:
Q is the amount of energy that we want to calculate
m is the mass of the iron sample which is 15 g
c is the specific heat capacity which is 0.448 J/g°C
ΔT is the change in temperature which is (100-22) = 78°C
Substituting the values, we have it as:
[tex]Q\text{ = 15 }\times\text{ 0.448 }\times\text{ 78 = 524.16 J}[/tex]