By definition, an equation has no solution when does not exist a value of the variable that makes the equation true.
• In this case, you have this expression on the left side of the first equation:
[tex]3x+6_{}_{}[/tex]
Then, knowing part of the right side, you can set up the following:
[tex]3x+6=3(x+1)[/tex]
Notice that you need to write a value different from 6, in order to make the equation false, In this case, you cannot complete the missing value with 2, because;
[tex]3\cdot2=6[/tex]
Then, having that equation. you can solve it as follows:
[tex]\begin{gathered} 3x+6=3x+3 \\ 3x-3x=3-6 \\ 0=-3\text{ (False)} \end{gathered}[/tex]
• Given the second equation that has this left side:
[tex]x-2[/tex]
The missing value must be:
