Answer
The Specific Heat of zinc = 11.11 J/g°C
Explanation
Given:
Mass of the zinc sample, m = 3 g
Quantity of heat, Q = 100 J
Initial temperature, T₁ = 22 °C
Final temperature, T₂ = 25 °C
The change in temperature, ΔT = T₂ - T₁ = 25 °C - 22 °C = 3 °C
What to find:
The Specific Heat of zinc, c
Step-by-step solution:
The Specific Heat of zinc, c can be calculated using the formula given below.Q=m
[tex]\begin{gathered} Q=mc\Delta T \\ \\ \Rightarrow c=\frac{Q}{m\Delta T} \end{gathered}[/tex]Putting the values of the given parameters into the formula, we have;c
[tex]c=\frac{100\text{ }J}{3g\times3°C}=\frac{100J}{9\text{ }g°C}=11.11\text{ }J\text{/}g°C[/tex]Hence, the Specific Heat of zinc is 11.11 J/g°C
