Respuesta :
To answer this question, we can proceed as follows:
1. We have that the perimeter of the rectangle is equal to 116cm, then, we have:
[tex]w+l+w+l=116\Rightarrow2w+2l=116[/tex]We know that a rectangle is a parallelogram. Then, its opposite sides are congruent.
2. We have that the length of the rectangle is 1 cm more than twice its width. We can translate this, algebraically, as follows:
[tex]l=2w+1[/tex]Now, to find the measures of the length and the width of the rectangle, we can substitute this last formula into the first one, as follows:
[tex]2w+2(2w+1)=116[/tex]We need to apply the distributive property to find w:
[tex]2w+4w+2=116[/tex]Adding like terms:
[tex]6w+2=116[/tex]Subtracting 2 to both sides of the equation, and then dividing by 6:
[tex]6w+2-2=116-2\Rightarrow6w=114\Rightarrow\frac{6w}{6}=\frac{114}{6}\Rightarrow w=19[/tex]Then, the width of the rectangle is equal to 19cm. The measure of the length can be calculated using either equation above. Let us use the first equation:
[tex]2w+2l=116\Rightarrow2\cdot19+2l=116\Rightarrow38+2l=116[/tex]Then, using similar properties as before, we have:
[tex]38-38+2l=116-38\Rightarrow2l=78\Rightarrow\frac{2l}{2}=\frac{78}{2}\Rightarrow l=39[/tex]In summary, we have that the measures of the length and width of this rectangle are:
• Width, ,(w) =, 19cm
,• Legth (l) = ,39cm
