Part A;
[tex]The\text{ mistake is there is the presence of 'and'.}[/tex]Part B;
[tex]Ben\text{ does not run track or he does not play football.}[/tex]Part C;
DeMorgan’s Laws: (negating AND and OR)
(The statements shown are logically equivalent.)
∼(p ∧ q) ↔ (∼p ∨ ∼q)
∼(p ∨ q) ↔ (∼p ∧ ∼q)
Notice that the negation symbol is distributed across the parentheses and the symbols are changed from AND to OR (or vice versa).