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Graph the parabola Y=x^ +2x -1Plot five points on the parabola the vertex the two points to the left of the vertex the two points to the right of the vertex then click on the graph a function button

Graph the parabola Yx 2x 1Plot five points on the parabola the vertex the two points to the left of the vertex the two points to the right of the vertex then cl class=

Respuesta :

Given the equation of the parabola

[tex]y=x^2+2x-1[/tex]

which can be written as

[tex]\begin{gathered} y=x^2+2x+1-1-1 \\ =(x+1)^2-2 \end{gathered}[/tex]

Comparing with

[tex]y=a(x-h)^2+k[/tex]

gives a = 1, h = -1 and k = -2.

The vertex is (h, k) = (-1, -2).

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