if a chemical reaction produces hydroxide ion, oh- , what would be the range for the target ph of a buffer solution that would favor ph stabilization under these conditions? explain your answer

Respuesta :

The range for the target ph of a buffer solution that would favours ph stabilization unders this condition in (4.75-4.85).

What is Henderson Hasselback equation ?

The Henderson-Hasselbalch equation, pH = pKa + log([A]/[HA]), can be used to determine the pH of a buffer. The terms "HA" and "A" in this equation stand for the equilibrium concentrations of the conjugate acid-base pair that were employed to make the buffer solution.

What is acetate?

A proton is taken out of the carboxy group of acetic acid to produce acetate, a monocarboxylic acid anion. It performs a function as a Saccharomyces cerevisiae metabolite as well as a human metabolite. The base is a conjugate of an acetic acid. ChEBI. Alternatives to ACETIC ACID

The Henderson Hasselback equation for a suitable acetic acid / acetate buffer-

Ph= Pka + log (salt)/(acid)

(salt) = (acetate)

(acid) = (acetic acid)

now, CH3 COOH dissociates as

CH3COOH ⇔ CH3COOH +H

Pka for CH3COOH = 4.75

If a chemical reaction produced hydroxide ions, then CH3COOH gets consumed and more acetate ions with produces. This leads to change in Ph of the solution as due (CH3C00H-) increases the ph absence increases.

The range for the target ph of a buffer solution that would favours ph stabilization unders this condition in (4.75-4.85)

The buffer capacity is the ability of a given buffer to resist any changes in ph when small amount of acid or base added to it.The buffer capacity of a mixed weak acid( here Acetic acid)-base (NaOH) buffer is much greater when the individual pKa values are in close proximity with each other.

Therefore, The range for the target ph of a buffer solution that would favours ph stabilization unders this condition in (4.75-4.85).

Learn more Henderson Hasselback equation about from the given link.

https://brainly.com/question/13423434

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