The required solution (1, 4) of a linear system of the equation is determined by the elimination method.
Given the linear system of equations:
8x - 2y = 0 or 4x - y = 0 …(i)
-6x + 14y = 50 or -3x + 7y = 25 …(ii)
Equations (i) and (ii) constitute a system of two first-degree equations in the two variables x and y.
So, we have to find out the value of 'x’ and 'y’.
By multiplying 7 by equation (i) and adding both equations
28x - 7y -3x + 7y = 25
25x = 25
x = 25/25
x = 1
Substitute the value of x = 1 in the equation (i), and solve for y
4(1) - y = 0
y = 4
Hence, the required solutions are x = 1 and y = 4.
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