N2 + 3H2 → 2NH3 1Mol N2 reacts with 3 mol H2 to produce 2 mol NH3 Determine the limiting reactant: Molar Mass N2 = 28.02 g/mol 14.01g N2 = 14.01*28.02 = 0.5 mol N2 This wiull react with 0.5*3 = 1.5 mol H2 Molar mass H2 = 2.015 g/mol 3.02g = 3.02/2.015 = 1.5 mol H2
You reactants are in stoichiometric balance ( as close as you can get). Therefore 0.5 mol N2 will produce 1.0 mol NH3 Molar mass NH3 = 14.0 + 1.01*3 = 17.03g NH3 produced - which is the mass of reactants because they are in stoichiometric balance.
