[tex]\mathbb P(X>154)=\mathbb P\left(\dfrac{X-130}{12}>\dfrac{154-130}{12}\right)=\mathbb P(Z>2)[/tex]
Since approximately 95% of any normal distribution falls within two standard deviations of the mean, it follows that 5% falls outside that range, with 2.5% to either side. So [tex]\mathbb P(Z>2)\approx0.025[/tex].
The actual value is a bit closer to 0.0228, but that's not very far off.
