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A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?

Respuesta :

Used an app called Mephyso to do the calculation.
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Answer:

Final speed of the ball, v = 19.2 m/s

Explanation:

Given that,

Acceleration of the ball, [tex]a=3.2\ m/s^2[/tex]

Initially, the ball is at rest, u = 0

Time, t = 6 s

We need to find the final speed of the ball. It can be calculated using first equation of motion as :

v = u + at

[tex]v=0+3.2\times 6[/tex]

v = 19.2 m/s

So, the final speed of the ball is 19.2 m/s. Hence, this is the required solution.