Find two consecutive even numbers such that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

38 and 40
40 and 42
42 and 44

Respuesta :

40 and 42..................

Answer:

The correct option is 2. The consecutive even numbers are 40 and 42.

Step-by-step explanation:

Let the two consecutive even numbers be x and x+2.

It is given that the difference of one-half the larger number and two-fifths the smaller number is equal to five.

[tex]\frac{1}{2}(x+2)-\frac{2}{5}(x)=5[/tex]

[tex]\frac{x+2}{2}-\frac{2x}{5}=5[/tex]

[tex]\frac{5x+10-4x}{10}=5[/tex]

[tex]x+10=50[/tex]

[tex]x=50-10[/tex]

[tex]x=40[/tex]

The value of x is 40. Therefore the two consecutive even numbers are 40 and 42.

Option 2 is correct.