The question is incomplete. Here, is the complete question:
A balloon has a volume of 253.2 mL at 356 K. The volume of the balloon is decreased to 165.4 mL. What is the new temperature?
Answer: The new temperature is 232.6 K.
Explanation:
Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.
[tex]V\propto T[/tex] (At constant pressure and number of moles)
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where,
[tex]V_1[/tex] = initial volume of gas = 253.2 ml
[tex]V_2[/tex] = final volume of gas = 165.4 ml
[tex]T_1[/tex] = initial temperature of gas= 356 K
[tex]T_2[/tex] = final temperature of gas = ?
Putting in the values:
[tex]\frac{253.2}{356}=\frac{165.4}{T_2}[/tex]
[tex]T_2=232.6K[/tex]
Therefore, the new temperature is 232.6 K.
