A ball is thrown from the top of a 50-ft building with an upward velocity of 24 ft/s. When will it reach its maximum height? How far above the ground will it be?

Respuesta :

24ft/s for the 1st second then it'd be 9.8mp/s which is the speed of velocity towards earth, so the 24ft/s - the 9.8 would be 14.2ft/s which is the second, the third would then be 4.4 after again subtracting 9.8. That is as far as I got, hope that helps even slightly