Answer : The correct sequence is,
[tex]\text{Acid}+\text{Base}\rightleftharpoons \text{Conjugate Base}+\text{Conjugate Acid}[/tex]
Explanation :
According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.
Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.
The given equilibrium reaction will be,
[tex]H_3BO_3(aq)+HS^-(aq)\rightleftharpoons H_2BO_3^-(aq)+H_2S(aq)[/tex]
In this reaction, [tex]H_3BO_3[/tex] is an acid that donate a proton or hydrogen to [tex]HS^-[/tex] base and it forms [tex]H_2BO_3^-[/tex] and [tex]H_2S[/tex] are conjugate base and acid respectively.
That means, [tex]H_3BO_3[/tex] and [tex]HS^-[/tex] are acid and base and [tex]H_2BO_3^-[/tex] and [tex]H_2S[/tex] are conjugate base and acid respectively.
The general sequence of Brønsted-Lowry acids and bases is:
[tex]\text{Acid}+\text{Base}\rightleftharpoons \text{Conjugate Base}+\text{Conjugate Acid}[/tex]
Hence, the correct sequence is,
[tex]\text{Acid}+\text{Base}\rightleftharpoons \text{Conjugate Base}+\text{Conjugate Acid}[/tex]
