Respuesta :
[tex] \sqrt{144} [/tex] is 12. so 12 is the length and width of the square.
To find the circumference: 12(diameter) * constant pi (3.14) = 37.68
37.68 is rounded to 37.7
the circumference of the circle is 37.7 m[tex] ^{2} [/tex]
To find the circumference: 12(diameter) * constant pi (3.14) = 37.68
37.68 is rounded to 37.7
the circumference of the circle is 37.7 m[tex] ^{2} [/tex]