Let x be the width of the rectangle, then (2x-4) = length.
[tex]x(2x-4)=160 \\ 2x^2-4x-160=0 \ \ |:2 \\ x^2-2x-80=0 \\ D=b^2-4ac=(-2)^2-4*1*80=4+320=324 \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ x_{1}= \frac{2- \sqrt{324} }{2}= \frac{2-18}{2}=-8 \ \ \ \O \\ x_{2}= \frac{2+ \sqrt{324} }{2}= \frac{2+18}{2}=10 \ units \ (width) \\ \\ length=2*10-4=16 \ units[/tex]
Answer: 16.
