Respuesta :
In light energy, the higher the frequency, the greater the energy a light contain.
We know for a certain that frequency is just the reciprocal of wavelength:
frequency = 1 / wavelength
Calculating for frequencies:
f UVA = 1/320 to 1/400
f UVA = 0.0031 to 0.0025
f UVB = 1/290 to 1/320
f UVB = 0.0034 to 0.0031
Since UVB has higher frequency range, then it has higher energy than UVA.
Answer:
uvb > uva > microwaves
Explanation:
The energy of an electromagnetic wave is
[tex]E =\frac{hc}{\lambda}[/tex]
Where
h is the Planck's constant
c is the speed of light and
[tex]\lambda[/tex] is the frequency
So we can understand that the energy is inversely proportional to the wavelength
The wavelengths are
1. microwaves - 1 mm - 1m
2. uva - 320 - 400 nm
3. uvb - 290 - 320 nm
So with the smallest wavelength the uvb has the greatest energy
and the microwave has least amount of energy with the largest wavelength range
so the answer is uvb > uva > microwaves