The reacting amount of oxygen is 7.3 grams.
First, we construct a reaction equation. This is:
4NH₃ + 5O₂ → 4NO + 6H₂O
Next, we find the moles of oxygen gas present, this is:
Moles = mass / Mr
Moles = 7.3 / 32
Moles = 0.23
The molar ratio of nitric oxide to oxygen is 4 : 5; using this, we find the moles of nitric oxide produced to be:
0.23 * 4/5
0.18 moles of nitric oxide
We find the mass using the same formula as above:
mass = 0.18 * 30
mass = 5.4 g
5.4 grams of nitric oxide will be produced.
