Respuesta :
1/3 x 9a then 1/3 x n plus -1/2 x 4a the -1/2 x 2b the add the two b's together then add the two a'S together the write _a + _b
1/3(9a+b) - 1/2(4a+2b) = (1/3)(9a+b) - (1/2)(4a+2b)
= (1/3).9a + (1/3)b - [(1/2).4a + (1/2).2b]
= 3a + b/3 - 2a - b
= a + (1/3 - 1)b
= a - (2/3)b
= (1/3).9a + (1/3)b - [(1/2).4a + (1/2).2b]
= 3a + b/3 - 2a - b
= a + (1/3 - 1)b
= a - (2/3)b