Answer: 82.4%
Step-by-step explanation: 14 wins and 3 losses. That means they had 17 games in total. 14/17 is 82.4 percent rounded to the thousands.
Answer:
82.353%
Step-by-step explanation:
To find the winning percentage, we use the formula:
[tex] \textsf{Winning Percentage} = \dfrac{\textsf{Number of Wins}}{\textsf{Total Number of Games}} \times 100\% [/tex]
Given that the Chiefs had 14 wins in a 17-game regular season:
So,
[tex] \textsf{Winning Percentage} = \dfrac{14}{17} \times 100\% [/tex]
[tex] \textsf{Winning Percentage} \approx \dfrac{14}{17} \times 100\% [/tex]
[tex] \textsf{Winning Percentage} \approx 82.35294118 [/tex]
[tex] \textsf{Winning Percentage} \approx 82.353\% \textsf{(in nearest thousandth)}[/tex]
Therefore, the Chiefs' winning percentage is approximately 82.353%.
