Respuesta :
. We know that Dante has twice as many jelly beans as Carlos, and Natalia has 4 more jelly beans than Carlos and Dante combined.
Let's say Carlos has x jelly beans.
According to the information given, Dante would have 2x jelly beans, and Natalia would have (x + 2x + 4) jelly beans.
Now, we can add up all the jelly beans: x + 2x + (x + 2x + 4) = 58.
Simplifying the equation, we get 6x + 4 = 58.
By solving for x, we find that Carlos has 9 jelly beans.
Let's say Carlos has x jelly beans.
According to the information given, Dante would have 2x jelly beans, and Natalia would have (x + 2x + 4) jelly beans.
Now, we can add up all the jelly beans: x + 2x + (x + 2x + 4) = 58.
Simplifying the equation, we get 6x + 4 = 58.
By solving for x, we find that Carlos has 9 jelly beans.
Answer:
Carlos has 9 jelly beans.
Let's denote the number of jelly beans Carlos has as C.
1. Dante has twice as many as Carlos, so Dante has 2C
2. Natalia has 4 more jelly beans than both Carlos and Dante together so she has:
(C+ 2C + 4) = 3C + 4
3. All together they have 58:
C + 2C + (3C + 4) = 58
4. Combining like terms:
6C + 4 = 58
6C = 54
C = 9