Respuesta :
Answer: 8
Explanation: M_1*V_1 = M_2*V_2
M_1 is given to be 4 M, and V_1 is what the problem wants. M_2 is .5 M and V_2 is 1 L. Plugging these into the equation gives us 4(V_1) = .5(1). 4/.5=8
0.125 L (with no sig figs)
I’m not sure if you’re familiar with the formula M1 x V1 = M2 x V2, but that is what will be using here.
Another good one to know is that moles= MV
(moles = Molarity times volume)
M is for Molarity and V is for volume, volume typically uses liters. So for this example we can set up an equation to find x. x L(4.0 M) = 1.0 L ( 0.50 M)
We multiply on the right.
x L (4.0 M) = 0.5 moles
And now divide both sides by 4.0
x = 0.5/4.0
x = 0.125 L
I’m not sure if you’re familiar with the formula M1 x V1 = M2 x V2, but that is what will be using here.
Another good one to know is that moles= MV
(moles = Molarity times volume)
M is for Molarity and V is for volume, volume typically uses liters. So for this example we can set up an equation to find x. x L(4.0 M) = 1.0 L ( 0.50 M)
We multiply on the right.
x L (4.0 M) = 0.5 moles
And now divide both sides by 4.0
x = 0.5/4.0
x = 0.125 L