Respuesta :
Hello there!
A = number of adults
C = number of children
Total number = A + C
A + C = 30
Total cost = A cost + C cost
Total cost = $50
Total cost = 3a + c
Equation: a + c = 30
3a + c = 50
2a = 20 A = 10
10 + c = 30
C = 20
The answer is
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 3a + c = 50
Hope This Helps You!
Good Luck :)
A = number of adults
C = number of children
Total number = A + C
A + C = 30
Total cost = A cost + C cost
Total cost = $50
Total cost = 3a + c
Equation: a + c = 30
3a + c = 50
2a = 20 A = 10
10 + c = 30
C = 20
The answer is
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 3a + c = 50
Hope This Helps You!
Good Luck :)
Answer:
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 3a + c = 50
[tex]total~ of ~adults ~and~ children~ was~ 30 : a + c = 30 $3 per adult, $1 per child....total of $50 : 3a + c = 50 a + c = 30 a = 30 - c -- now sub 30 - c in for a in the other equation 3a + c = 50 3(30 - c) + c = 50 -- distribute through the parenthesis 90 - 3c + c = 50 -- subtract 90 from both sides -3c + c = 50 - 90 -- simplify -2c = - 40 -- divide both sides by -2 c = 20 a + c = 30 a + 20 = 30 a = 30 - 20 a = 10 so there are 20 children and 10 adults[/tex]
20 children and 10 adults
Equation 1: a + c = 30
Equation 2: 3a + c = 50
[tex]total~ of ~adults ~and~ children~ was~ 30 : a + c = 30 $3 per adult, $1 per child....total of $50 : 3a + c = 50 a + c = 30 a = 30 - c -- now sub 30 - c in for a in the other equation 3a + c = 50 3(30 - c) + c = 50 -- distribute through the parenthesis 90 - 3c + c = 50 -- subtract 90 from both sides -3c + c = 50 - 90 -- simplify -2c = - 40 -- divide both sides by -2 c = 20 a + c = 30 a + 20 = 30 a = 30 - 20 a = 10 so there are 20 children and 10 adults[/tex]
