Respuesta :
(x + 5)(2x - 3) =
x(2x - 3) + 5(2x - 3) =
2x^2 - 3x + 10x - 15 =
2x^2 + 7x - 15........so b = 7 <==
x(2x - 3) + 5(2x - 3) =
2x^2 - 3x + 10x - 15 =
2x^2 + 7x - 15........so b = 7 <==