Bennewhouse6
Bennewhouse6
02-09-2015
Mathematics
contestada
3(2j-k) = 108, for j
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konrad509
konrad509
02-09-2015
[tex]3(2j-k)=108\\ 2j-k=36\\ 2j=36+k\\ j=18-\dfrac{k}{2}[/tex]
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