jaeybird9
contestada

The coordinates of the vertices of a polygon are (−2,1), (−3,3), (−1,5), (2,4), and (2,1).



What is the perimeter of the polygon to the nearest tenth of a unit?



15.2 units

15.9 units

16. 5 units

18.8 units

Respuesta :

Everest2017
Name them as vertices A,B,C , D and E in that order.

[tex]ab = \sqrt{ {( - 2 + 3)}^{2} + (1 - 3)^{2}} = \sqrt{5} \\ bc = \sqrt{ {( - 3 + 1)}^{2} + {(3 - 5)}^{2} } = 2 \sqrt{2} \\ cd = \sqrt{ { (- 1 - 2)}^{2} + {(5 - 4)}^{2} } = \sqrt{10} \\ de = \sqrt{ {(2 - 2)}^{2} + {(4 - 1)}^{2} } = 3 \\ ea = \sqrt{ {(2 + 2)}^{2} + {(1 - 1)}^{2} } = 4 \\ peimeter = ab + bc + cd + de + ea = 15.227 \: or \: 15.23[/tex]
budwilkins

[tex] \sqrt{5} + 2 \sqrt{2} + \sqrt{10} + 3 + 4 \\ = 2.24 + 2.83 + 3.16 + 3 + 4 \\ = 8.23 + 7 = 15.23[/tex]
So the best rounded answer to nearest tenth is: A) 15.2 units

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