ould use the margin of error formula so that we can solve for the sample size yielding necessary results for an accurate specified confidence and margin of error.
The formula for margin of error is:
E = Za/2 * standard deviation / sqrt n
So we are going to change this into
n = [Za/2 * standard dev / Margin of error] ^2
so for a 95% confidence interval we have an alpha equivalent to = 0.05
so a/2 = 0.025. the critical value for this is 1.960
let our margin of error be 1 and the standard deviation be 1
so plugging in our data:
n = [1.96 * 15 / 1] ^2
= 864.36 or 864
