Respuesta :
Answer is: 0,327 g/l.
Ideal gas law: pV = nRT.
V - volume, the amount of space occupied by the gas.
p - pressure ,1 atm = 760 torr = 760 mmHg.
n - amount of substance.
T - temperature, 273 K = 0°C. T = 25 + 273 = 298K.
R - ideal gas constant, R = 0,08206 L·atm/mol·K.
d(He) = M·p ÷ R·T.
d - density.
M - molar mass.
d(He) = 4g/mol · 2atm ÷ 298K · 0,08206 L·atm/mol·K = 0,327 g/l.
Ideal gas law: pV = nRT.
V - volume, the amount of space occupied by the gas.
p - pressure ,1 atm = 760 torr = 760 mmHg.
n - amount of substance.
T - temperature, 273 K = 0°C. T = 25 + 273 = 298K.
R - ideal gas constant, R = 0,08206 L·atm/mol·K.
d(He) = M·p ÷ R·T.
d - density.
M - molar mass.
d(He) = 4g/mol · 2atm ÷ 298K · 0,08206 L·atm/mol·K = 0,327 g/l.
The density of He gas is 0.33 g/L.
The density of the gas is obtainable from the formula;
PM = dRT
Where;
P = pressure of the gas
M = molar mass of the gas
d = density of the gas
R = gas constant
T = temperature
The values are;
P = 1521 mmHg or 2 atm
M = 4 g/mol
d = ?
R = 0.082 atmLK-1mol-1
T = 25.0◦c or 298 K
Substituting values;
d = PM/RT
d = 2 atm × 4 g/mol/ 0.082 atmLK-1mol-1 × 298 K
d = 0.33 g/L
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