Respuesta :
2. The x-coordinate of the solution is 3
4. The y-coordinate of the solution is 4
5. The ordered pair that is the solution to the system lies is quadrant I
Proof:
Solve the following system:
{8 x + 6 y = 48 | (equation 1)
{2 x - 3 y = -6 | (equation 2)
Subtract 1/4 × (equation 1) from equation 2:
{8 x + 6 y = 48 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 24 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Multiply equation 2 by -2/9:
{4 x + 3 y = 24 | (equation 1)
{0 x+y = 4 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 12 | (equation 1)
{0 x+y = 4 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3 | (equation 1)
{0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 3, y = 4
Solve the following system:
{8 x + 6 y = 48 | (equation 1)
{2 x - 3 y = -6 | (equation 2)
Subtract 1/4 × (equation 1) from equation 2:
{8 x + 6 y = 48 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 24 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Multiply equation 2 by -2/9:
{4 x + 3 y = 24 | (equation 1)
{0 x+y = 4 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 12 | (equation 1)
{0 x+y = 4 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3 | (equation 1)
{0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 3, y = 4
4. The y-coordinate of the solution is 4
5. The ordered pair that is the solution to the system lies is quadrant I
Proof:
Solve the following system:
{8 x + 6 y = 48 | (equation 1)
{2 x - 3 y = -6 | (equation 2)
Subtract 1/4 × (equation 1) from equation 2:
{8 x + 6 y = 48 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 24 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Multiply equation 2 by -2/9:
{4 x + 3 y = 24 | (equation 1)
{0 x+y = 4 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 12 | (equation 1)
{0 x+y = 4 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3 | (equation 1)
{0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 3, y = 4
Solve the following system:
{8 x + 6 y = 48 | (equation 1)
{2 x - 3 y = -6 | (equation 2)
Subtract 1/4 × (equation 1) from equation 2:
{8 x + 6 y = 48 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Divide equation 1 by 2:
{4 x + 3 y = 24 | (equation 1)
{0 x - (9 y)/2 = -18 | (equation 2)
Multiply equation 2 by -2/9:
{4 x + 3 y = 24 | (equation 1)
{0 x+y = 4 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{4 x+0 y = 12 | (equation 1)
{0 x+y = 4 | (equation 2)
Divide equation 1 by 4:
{x+0 y = 3 | (equation 1)
{0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 3, y = 4