Respuesta :
Volume of a triangular pyramid=(1/3)Bh
B=base=area of the triangle located in the base=(1/2)(base)(height)=
=(9 cm)(15 cm)/2=67.5 cm²
height=32 cm
Volume=(1/3)/(67.5 cm²)(32 cm)=720 cm³
Answer: 720 cm³
B=base=area of the triangle located in the base=(1/2)(base)(height)=
=(9 cm)(15 cm)/2=67.5 cm²
height=32 cm
Volume=(1/3)/(67.5 cm²)(32 cm)=720 cm³
Answer: 720 cm³
Answer:
Option A is correct
720 [tex]\text{cm}^3[/tex] is the volume of the pyramid
Step-by-step explanation:
Volume of a triangular pyramids is given by:
[tex]V = \frac{1}{3}Bh[/tex] ......[1]
where
V is the volume of the triangular pyramid
B is the base area
h is the height of the pyramids
From the given figure:
h = 32 cm
to find the Area of the base.
Use formula:
[tex]B = \frac{1}{2}xy[/tex]
where x represents the width and y represents the height of the Base in the pyramids.
Here, x = 9 cm and y = 15 cm
then;
[tex]B = \frac{1}{2}(9)(15)=\frac{135}{2}[/tex] centimeter square.
Substitute the value of B in [1] we get;
[tex]V = \frac{1}{3}\cdot \frac{135}{2} \cdot 32 = 45 \cdot 16[/tex]
Simplify:
V = 720 centimeter cube
Therefore, the volume of the given pyramids is 720 [tex]\text{cm}^3[/tex]