Respuesta :
Using the Definition of Potency, we have:
[tex]P= \frac{V^2}{R} [/tex]
Entering the unknowns:
[tex]P= \frac{V^2}{R} \\ 900*W= \frac{(120*V)^2}{R} \\ R= \frac{14400*V^2}{900*V*A} \\ R=16* \frac{V}{A} \\ \boxed {R=16Ohm}[/tex]
If you notice any mistake in my english, please let me know, because i am not native.
[tex]P= \frac{V^2}{R} [/tex]
Entering the unknowns:
[tex]P= \frac{V^2}{R} \\ 900*W= \frac{(120*V)^2}{R} \\ R= \frac{14400*V^2}{900*V*A} \\ R=16* \frac{V}{A} \\ \boxed {R=16Ohm}[/tex]
If you notice any mistake in my english, please let me know, because i am not native.
Answer : Resistance is 16 ohms.
Explanation :
It is given that,
Power of toaster, [tex]P=900\ Watt[/tex]
Voltage, [tex]V=120\ V[/tex]
According to ohm's law, V = I R
Mathematically power is defined as :
[tex]P=\dfrac{V^2}{R}[/tex]
or
[tex]R=\dfrac{V^2}{P}[/tex]
[tex]R=\dfrac{(120\ V)^2}{900\ W}[/tex]
[tex]R=16\ \Omega[/tex]
So, the resistance of the toaster is 16 ohms.
Hence, this is the required solution.
