Respuesta :

AL2006

In each game, the first team can be any one of the  12 ,
and the second team can be any one of the remaining  11 .

Total number of ways to match them up = (12 x 11) = 132 .

BUT ... Every game can be described as two different match-ups ...
either as ' A ' playing ' B' , or as ' B ' playing ' A '.

Although there are 132 ways to make a match-up, every possible
pair of teams shows up twice in that list. 

So in order for every team to play every other team, there are
only  (132 / 2) = 66 different games required.

Answer:Jaguar

Step-by-step explanation: