unit price = [tex] \frac{200}{q} [/tex] + 3
number of units = q
Revenue > $9000
Therefore,
q · ([tex] \frac{200}{q} [/tex] +3) > 9000
⇒ 200 + 3q > 9000
3q > 9000 - 200
3q > 8800
q > 2,933.3
Therefore, the minimum number of units that must be sold in order that sales revenue be greater than $9000 is 2,934 (Number of goods must be an integer)