Answer : The perimeter and the area of the polygon with the given vertices is, 24 unit and 36 unit² respectively.
Step-by-step explanation :
First we have to calculate the distance of JK, KL, LM and MJ.
Using distance formula:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where,
d = distance between the two coordinates
x and y are the coordinates.
To calculate the distance of JK:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(7-1)^2+(2-2)^2}[/tex]
[tex]d=\sqrt{(6)^2+(0)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
To calculate the distance of KL:
[tex]d=\sqrt{(x_3-x_2)^2+(y_3-y_2)^2}[/tex]
[tex]d=\sqrt{(7-7)^2+(8-2)^2}[/tex]
[tex]d=\sqrt{(0)^2+(6)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
To calculate the distance of LM:
[tex]d=\sqrt{(x_4-x_3)^2+(y_4-y_3)^2}[/tex]
[tex]d=\sqrt{(1-7)^2+(8-8)^2}[/tex]
[tex]d=\sqrt{(-6)^2+(0)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
To calculate the distance of MJ:
[tex]d=\sqrt{(x_4-x_1)^2+(y_4-y_1)^2}[/tex]
[tex]d=\sqrt{(1-1)^2+(8-2)^2}[/tex]
[tex]d=\sqrt{(0)^2+(6)^2}[/tex]
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
The distance of JK, KL, LM and MJ is, 6, 6, 6 and 6.
Now we have to calculate the perimeter of the polygon.
Perimeter of polygon = JK + KL + LM + MJ
Perimeter of polygon = 6 + 6 + 6 + 6
Perimeter of polygon = 24 unit.
Now we have to calculate the area of polygon.
As the distance between the coordinates are equal that means the geometry will be square because in square the all four sides are equal.
Now we have to calculate the area of polygon by using area of square formula.
Area of polygon = Area of square = (side)²
Given: Side = 6
Area of polygon = Area of square = (6)²
Area of polygon = Area of square = 36 unit²
Thus, the area of polygon is, 36 unit²
