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The function graphed approximates the height of an acorn, in meters, x seconds after it falls from a tree.

After about how many seconds is the acorn 5 m above the ground?

The function graphed approximates the height of an acorn in meters x seconds after it falls from a tree After about how many seconds is the acorn 5 m above the class=

Respuesta :

carlosego
For this case, the first thing to do is observe the vertical axis.
 We look for a height of 5 meters on the vertical axis.
 When finding the height of 5 meters we must observe for what time value this height belongs.
 For this, we observe the horizontal axis.
 The value of time is approximately:
 t = 1.7 seconds
 Answer:
 t = 1.7 seconds
 option 3

The equation of the parabola is y = – 5x² + 20. The time when an acorn is 5 m above the ground in 1.7 seconds. Then the correct option is C.

What is the parabola?

It is the locus of a point that moves so that it is always the same distance from a non-movable point and a given line. The non-movable point is called focus and the non-movable line is called the directrix.

The function graphed approximates the height of an acorn, in meters, x seconds after it falls from a tree.

We know that the equation of the parabola will be given as

y = a(x - h)² + k

where (h, k) is the vertex of the parabola and a is the constant.

We have

(h, k) = (0, 20)

Then

y = ax² + 20

The parabola is passing through (2, 0), then we have

0 = 4a + 20

a = -5

Then we have

y = – 5x² + 20

The time in seconds when the acorn is 5 m above the ground.

–5x² + 20 = 5

       –5x² = –15

             x = 1.7

More about the parabola link is given below.

https://brainly.com/question/8495504

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