1. Let the width be w. The length will be given by:
(80-2w)/2=40-w
given that the diagonal that is perpendicular to one side is 20 cm, the value of the unknown in the above equation will be:
40-w=20
w=20
hence the value of the length will be 40-w=40-20=20 cm
2]The number is (k+2) the square root of this number is √(k+2)
√(k+2)=2√(k-1)
squaring both sides gives
(k+2)=4(k-1)
k+2=4k-4
4k-k=4+2
3k=6
k=2
3] let the smaller number be x, the bigger number is x+1
√x=x+1-3
√x=(x-2)
x=x²-4x+4
0=x^2-5x+4
solving the quadratic we get:
x=1 or x=4
the first number is either 1 or 4, the second number is either 2 or 5
but since
√1≠(2-3)
then the answer is:
first number is 4, second number is 5