Respuesta :
First num= x ,second num=y
X+2y=10
2x+y=32
Use equation 1 in equation 2
X=10-2y
2(10-2y)+y=32
20-4y+y=32
-3y = 12
Y= -4
X+2(-4)=10
X=10+8
X=18
Firstnum = 18 , second num= -4
X+2y=10
2x+y=32
Use equation 1 in equation 2
X=10-2y
2(10-2y)+y=32
20-4y+y=32
-3y = 12
Y= -4
X+2(-4)=10
X=10+8
X=18
Firstnum = 18 , second num= -4
Let first number be x
And the second number be y
Then, x + 2y = 10.
⇒ x = 10- 2y....(1)
Also, 2x + y = 32 ...(2)
From, equation (1) & (2) we get,
2(10-2y) + y = 32
or 20 - 4y + y =32
or 20 - 32 = 3y
or y = 4
Therefore, x = 10- 2y
or x = 10-2*4
or x = 10 - 8
or x = 2
Therefore, the two numbers are 2 & 4
And the second number be y
Then, x + 2y = 10.
⇒ x = 10- 2y....(1)
Also, 2x + y = 32 ...(2)
From, equation (1) & (2) we get,
2(10-2y) + y = 32
or 20 - 4y + y =32
or 20 - 32 = 3y
or y = 4
Therefore, x = 10- 2y
or x = 10-2*4
or x = 10 - 8
or x = 2
Therefore, the two numbers are 2 & 4