Respuesta :
[tex]a = \frac{v}{t} [/tex]
v1=2.7 m/s
v2=4.8 m/s
t=3.5 secs
Then:
a=v2-v1/t
a=4.8-2.7/3.5
a=0.6 m/s²
Acceleration is rate of change of velocity with respect to change in time. The acceleration of the considered fox is given by: Option A. 0.6 m/s²
How to find the acceleration of an object?
If the object has constant acceleration, then it is calculated as:
[tex]a = \dfrac{\delta v}{\delta t} \: \rm \text{unit distance}/\text{unit time}^2[/tex]
where [tex]\delta t[/tex] = change in time and [tex]\delta v[/tex] = change in corresponding velocity of that object in consideration.
Thus, for the given case, as it is specified that:
- Initial velocity of the fox = 2.7 m/s
- Final velocity of the fox after 3.5 seconds = 4.8 m/s
Thus, we get [tex]\delta t[/tex] = time interval's length = 3.5 seconds,
and [tex]\delta v[/tex] =4.8 - 2.7 = 2.1 m/s
Thus, acceleration of fox is calculated as:
[tex]a = \dfrac{\delta v}{\delta t} = \dfrac{2.1}{3.5} = 0.6 \: \rm m/s^2[/tex]
Thus, the acceleration of the considered fox is given by: Option A. 0.6 m/s²
Learn more about acceleration here:
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