Respuesta :
The probability is 0.08.
The probability that the first roll is a 4 is 1/6, since there is one 4 out of six total possibilities.
The probability that the second roll is an even number is 3/6, since there are 3 even numbers out of 6 possibilities.
Together, we have 1/6(3/6) = 3/36 = 0.08
The probability that the first roll is a 4 is 1/6, since there is one 4 out of six total possibilities.
The probability that the second roll is an even number is 3/6, since there are 3 even numbers out of 6 possibilities.
Together, we have 1/6(3/6) = 3/36 = 0.08
[tex] |\Omega|=6^2=36\\
|A|=1\cdot3=3\\\\
P(A)=\dfrac{3}{36}=\dfrac{1}{12}\approx8.3\% [/tex]