Respuesta :
To solve the problem we must find the equation of the circumference of the form:
(Xa) ² + (Yb) ² = r²
They do not give us the center or the radio, but we have 3 points.
With the points H (-4,1), G (-2, -3) and C (5, -2) we find 3 equations
1) (-4-a) ² + (1-b) ² = r²
2) (-2-a) ² + (-3-b) ² = r ²
3) (5-a) ² + (-2-b) ² = r ²
Now we have a system of 3 equations with 3 unknowns: r, a, b
When solving the system we have to:
r = 5
a = 1
b = 1
Therefore, the center of the circumference of the lake is the point (a, b)
That is, the point (1,1)
(Xa) ² + (Yb) ² = r²
They do not give us the center or the radio, but we have 3 points.
With the points H (-4,1), G (-2, -3) and C (5, -2) we find 3 equations
1) (-4-a) ² + (1-b) ² = r²
2) (-2-a) ² + (-3-b) ² = r ²
3) (5-a) ² + (-2-b) ² = r ²
Now we have a system of 3 equations with 3 unknowns: r, a, b
When solving the system we have to:
r = 5
a = 1
b = 1
Therefore, the center of the circumference of the lake is the point (a, b)
That is, the point (1,1)
Answer:
The coordinates of the center of the lake are [tex](\frac{-1}{3},\frac{-4}{3})[/tex].
Step-by-step explanation:
It is given that Hillman Peak, Garfield Peak, and Cloudcap are three mountain peaks on the rim of the lake. The peaks are located in a coordinate plane at H(-4,1), G(-2,-3), and C(5,-2).
If we joint these points, then we get a triangle and the center of a triangle is known as centroid.
The formula for centroid of a triangle is
[tex]Centroid=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})[/tex]
The centroid of the triangle H(-4,1), G(-2,-3), and C(5,-2) is
[tex]Centroid=(\frac{-4-2+5}{3},\frac{1-3-2}{3})[/tex]
[tex]Centroid=(\frac{-1}{3},\frac{-4}{3})[/tex]
Therefore the coordinates of the center of the lake are [tex](\frac{-1}{3},\frac{-4}{3})[/tex].