Respuesta :
Hydrolysis of [tex]NH_{4}ClO_{4}[/tex] is given as:
[tex]NH_{4}ClO_{4}+H_{2}O\rightleftharpoons NH_{4}OH + HClO_{4}[/tex]
Here, [tex]NH_{4}OH[/tex] is a weak base and [tex]HClO_{4}[/tex] is a strong acid. Thus, solution is more acidic
Hydrolysis of [tex]KBr[/tex] is given as:
[tex]KBr+H_{2}O\rightleftharpoons KOH + HBr[/tex]
Here, [tex]KOH[/tex] is a strong base and [tex]HBr[/tex] is a strong acid.Thus, solution is neutral.
Hydrolysis of [tex]NaCl[/tex] is given as:
[tex]NaCl+H_{2}O\rightleftharpoons NaOH + HCl[/tex]
Here, [tex]NaOH[/tex] is a strong base and [tex]HCl[/tex] is a strong acid.Thus, solution is neutral.
[tex]Na_{2}CO_{3}+2H_{2}O\rightleftharpoons 2NaOH + H_{2}CO_{3}[/tex]
Here, [tex]NaOH[/tex] is a strong base and [tex]H_{2}CO_{3}[/tex] is a weak acid.Thus, solution is basic.
[tex]NaHCO_{3}+H_{2}O\rightleftharpoons NaOH + H_{2}CO_{3}[/tex]
Here, [tex]NaOH[/tex] is a strong base and [tex]H_{2}CO_{3}[/tex] is a weak acid.Thus, solution is basic.
Hence, an aqueous solution of [tex]NaHCO_{3}[/tex] and [tex]Na_{2}CO_{3}[/tex] will produce a basic solution.
