At [tex]T=0^{\circ}C[/tex], the volume of the gas is V=22 L.
At temperature [tex]T=1C[/tex], the volume of the gas is (22+225) L.
This means that if we increase the temperature by [tex]k[/tex] degrees:
[tex]T=k^{\circ}C[/tex]
the volume of the gas is
[tex]V=22 + 225 k [L][/tex] (1)
Since T=k, we can rewrite eq.(1) as
[tex]V= 22 + 225 T [L][/tex]
which gives the expression for the volume of the gas in liters, as a function of the temperature T in Celsius.
