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jourdynnshermap86x63 jourdynnshermap86x63

04-05-2018
Mathematics

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gmany gmany · Answer 1 · 2018-05-04T08:32:10+02:00

gmany gmany

04-05-2018

10.
[tex]x^2+14x+48=x^2+6x+8x+48=x(x+6)+8(x+6)=\boxed{(x+6)(x+8)}[/tex]

11.
[tex]\dfrac{t^2-4t-32}{t-8}=\dfrac{t^2-8t+4t-32}{t-8}=\dfrac{t(t-8)+4(t-8)}{t-8}\\\\=\dfrac{(t-8)(t+4)}{t-8}=t+4\\\\Answer:\boxed{t+4;\ t\neq8}[/tex]

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